Simple GoAsm question

[Paul]

Hi All,

Why can't I define a byte whose leftmost bit (sign bit) is one? E.g., defining

   DB A9h

gives GoAsm error:

Data declaration too small assuming it should hold at least a 32-bit address:- DB A9h

I think I know what's going on here. But it's awkward not being able to define individual bytes of any value.

Thanks.

Cordially,

Paul

[donkey]

If you are using HEX, it must always start with a digit from 0..9 so it would be

DB 0A9h

you can also use the alternate syntax

DB 0xA9

This is to differentiate numbers from labels (which cannot start with digits 0..9)

Edgar

[Paul]

Marvelous! Thank you very much.

-Paul

[1rDirEctoALgran0]

I agree with the first post of Paul.
What is the real meaning of this error message ?
It's very annoying... :eek

Patrick

[donkey]

I agree with the first post of Paul.
What is the real meaning of this error message ?
It's very annoying... :eek

Patrick

The error message makes perfect sense, since A9h has to be a label because it starts with a letter, GoAsm assumes it is a 32 bit address which will not fit in a byte. Remember that goasm allows a label to be used in the data section without OFFSET:

hInstance DD ?
phInstance DD hInstance

would move the 32 bit pointer to hInstance into phInstance.