Solving expressions

[RuiLoureiro]

anyone tried this

Code Select Expand


mov eax,some_value
xor ecx,ecx
div ecx


I dunno if Im making mistake, but it create a fault on the processor. Anyone experiencing that? I did.

          No, but i think it gives a fault

[dedndave]

divide by zero is the highest priority condition that x86 CPU's trap   :P
that's why it generates INT0

[oex]

X^0=1                   0^X=0
(Why except 0?)         (Why except 0?)

:lol Because you cant divide by 0.... There are other arguements.... Looks like this one was Euler's....

http://www.faqs.org/faqs/sci-math-faq/specialnumbers/0to0/
http://en.wikipedia.org/wiki/Division_by_zero

[RuiLoureiro]

:lol Because you cant divide by 0.... There are other arguements.... Looks like this one was Euler's....

oex,
         For me y^x is an indeterminate form when y=0 and x=0.
         For me 0^0 is not 1. I dont follow your point of view.
         If for convenience you want it 1, yes you can why not ?
         Play with 0^0+0^0+0^0+0^0+0^0=5 why not ?

[oex]

:lol This is OK I dont believe I've ever typed 0^0 before now I was just trying to show you/others the other points, mathmatic and programatic, logical and illogical.... My own expression evaluator uses 0^0=1 but there is no 'right' result, following your posts I may well update this to better error check different scenarios ie 1+0^0=1 but 10*0^0=10.... Currently however my code calculates:

0^0+0^0+0^0+0^0+0^0=5 yes

However in a more usual situation
10*0^0=10 and 0^0 is 'ignored'

This is more important for my expression evaluator as it also does more complex functionality however it really does depend on context what is the right result....

[RuiLoureiro]

i typed 0^0 in all my calculators and they all give ERROR
They dont want to say nothing about it
I play with 1^1+1^1+1^1+1^1+1^1=5

Have a nice new year