I am using the easy code and I have 1) a Window of course. 2) A button. 3) a WindowEdit1 control
My intention is send a messge to de edit1 control when the user push the button.
.data
mytext db " Good morning....",0
This is my code
Window1Edit1 Proc Private hWnd:HWND, uMsg:ULONG, wParam:WPARAM, lParam:LPARAM
Return FALSE
Window1Edit1 EndP
Window1Button1 Proc Private hWnd:HWND, uMsg:ULONG, wParam:WPARAM, lParam:LPARAM
lea edx,mytext
Invoke SendMessage, hWnd, WM_SETTEXT, 0, Edx
Return FALSE
Window1Button1 EndP
But here I don´t know which is the value for hWnd. The Edit1 control was made by drag and drop from the toolbox.
Best regards
I don't have much experience with EasyCode, but I will assume that you are creating a dialog and some controls within. If this is the case, then the return value from CreateDialogParam will be the handle of main window, and to get the hWnd (Window handle) for any controls, you may use GetDlgItem, with first argument set to the main window's handle and second filled with the ID of the control (most probablly in design mode, in Properties window you can find this value). However, just to get or set the text in a control you can use GetDlgItemText and SetDlgItemText instead of WM_...
Regards,
Nick
hi
try this
invoke GetDlgItem,hWnd,1000 ;id to your edit1
mov edi,eax ;the handle of your edit
lea edx,mytext
Invoke SendMessage, edi, WM_SETTEXT, 0, edx
greets
ragdog