Help Request

[spaarkz]

Hi

I am using the following code as part of a program to request a user to enter two separate intergers and then output the sum on the screen.

    mov         al,         num1
    add         al,         num2
    mov         result,     al

When the two intergers are inputtted for example 1, 1 the output is the char 'b' instead of 2 and if 1, 2 is entered the output is char 'c' instead of the interger 3.

Can anyone explain what I am doing wrong?

Thanks

[BasilYercin]

1 = 31h
2 = 32h
3 = 33h

31h + 32h = 63h

you have to convert your ascii number in numbers

[spaarkz]

I see...So if i enter two decimal numbers on the keyboard the computer stores them as hex.

1 = 31h and 2 = 32h which = 63h

So before I can out put a decimal on the screen I need to subtract 30h from the sum.

Just tried it and it works thanks.

[Mark Jones]

Hi, to process numbers larger than 255, consider something like this:

Code Select Expand

.data?
    szVal1          dd  12 dup (?)
    szVal2          dd  12 dup (?)
    nVal1           dd  ?
    nVal2           dd  ?
    szResult        dd  ?
.code
    mov szVal1,chr$("12345678")         ; put some ascii values in our
    mov szVal2,chr$("87654321")         ; two strings
    invoke atodw,[szVal1]               ; convert both to dwords, note
    mov [nVal1],eax                     ; ADDR must not be used with szVal,
    invoke atodw,[szVal2]               ; even though these are strings
    mov [nVal2],eax                     ; save second decimal value
    add eax,[nVal1]                     ; "add" the second to the first
    invoke dwtoa,eax,addr szResult      ; convert this dword back to ascii
    invoke MessageBox,0,addr szResult,0,MB_OK ; display it