For Loop To Assembly

[Shooter]

So, why IS he getting 650 as an answer in his original sample?

[clive]

So, why IS he getting 650 as an answer in his original sample?

Because the C/C++ code is correct, the first assembler version adds the sum to ebx which it doesn't need too, and then prints the value in ebx instead of the one in sum.

Or am I missing your point?

To extend Lingo's solution for different values of N, we could make a table. The point however is to understand the math.

Sum at each iteration :

Code Select Expand

0 :    0
1 :    2
2 :    6
3 :   12
4 :   20
5 :   30
6 :   42
7 :   56
8 :   72
9 :   90
10 :  110
11 :  132
12 :  156
13 :  182
14 :  210
15 :  240
16 :  272
17 :  306
18 :  342
19 :  380
20 :  420
21 :  462
22 :  506
23 :  552
24 :  600
25 :  650

Where he got 675 was from iteration ebx = 25, ebx += sum (650), ebx = 675

[jwill22]

Sorry for being so late...but thanks you all..You really helped me out :dance: :dance: :dance: