DLL with polink: Unresolved external symbol

[jj2007]

I am trying to produce a very simple dll. It works fine with link.exe but fails with polink:

Unresolved external symbol '_SayHello'

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include \masm32\include\masm32rt.inc

.code
LibMain proc instance:DWORD, reason:DWORD, unused:DWORD
    mov eax, TRUE
    ret
LibMain endp

SayHello proc EXPORT MyText:DWORD
    invoke MessageBox, 0, MyText, chr$("I sit in a dll!"), MB_OK
    ret
SayHello endp

end LibMain

My def file is as follows:

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LIBRARY "MiniDll"
EXPORTS
SayHello


Commandline:
\Masm32\bin\polink.exe /Subsystem:Windows /DLL /DEF:TmpDllEx.def  "MiniDll.obj" /OUT:MiniDll.dll

All that works perfectly with link.exe, versions 5.12 and 9.00

Any ideas?

[dedndave]

hiyas Jochen,
i am guessing the "_" decorator may have something to do with it
Erol is the guy to ask, of course - lol

[Vortex]

Hi Jochen,

No need to use a module definition file if you specify the EXPORT keyword below :

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SayHello proc EXPORT MyText:DWORD

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\masm32\bin\ml /c /coff MiniDLL.asm
\masm32\bin\polink /SUBSYSTEM:WINDOWS /DLL MiniDLL.obj

Linker : Polink Version 6.00.1

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[jj2007]

Hi Erol,

With your settings, it builds the dll but the exports are decorated:

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this will work: mov pSayHello, rv(GetProcAddress, hDll, chr$("_SayHello@4"))
this does not work: mov pSayHello, rv(GetProcAddress, hDll, chr$("SayHello"))


The commandline /DLL /DEF:TmpDllEx.def will produce the "unresolved" error, if I uise only /dll, it links fine but again, I have the decorated names. How can I get rid of the decoration?

P.S.: The export.txt is apparently not needed, and has no influence on the result.

EDIT:

SayHello proc EXPORT MyText:DWORD

It works fine when I use the /def:Myfile.def option and take away the export keyword (the latter does not disturb link.exe...).

Edit(2): For RichMasm (see TheGuide, MiniDLL), I found a solution that works fine for link.exe and polink.exe:

SayHello proc MyText:DWORD  ; $export

The editor will create the .def file based on the names of those procedures that have $exp in the same line as the proc itself.